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Question

Submitted 327 days ago...

Bagger929

Bagger929

New User (1)

Electrochemistry

An aqueous solution of an unknown salt of vanadium is electrolyzed by a current of 2.50 amps for 1.50 hours. the electroplating is carried out with an efficency of 95.0 %, resulting in a deposit of 2.251 g. of Vanadium.
How many faradays are required to deposit the vanadium?

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Answer 1 / 1 - Submitted 326 days ago...

explicit

explicit

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We need to define a Faraday first. This is a gram mole of electrons and is equal to 96,500 coulombs where one coulomb is the number of electrons that flow past a given point in one second when the current is 1 ampere. Thus for 2.5 amperes for 1.5 hours the number of coulombs is 2.5*1.5*3600 = 13,500 which converts to 0.14 Faradays. This is the total quantity of electrons used to deposit the vanadium. The "useful" amount is 95% of this value while 5% was lost as heat. You dont need to know that the salt was vanadium nor do you need to know the mass of metal deposited to get the answer.

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Electrochemistry

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